Question

In the adjoining figure, find the area of the shaded region.​

Answer 1

➲ °•Concept:-

Let's

There was a Rectangular field a person wants to build a House Type of a Square , There was a Rectangle and a square. Length of rectangle is 26 Cm and Breadth of rectangle is 16 Cm .

The sides of the square is 9cm . First find the area of rectangle by formula ( Length×Breadth)

Then fInd the area of square by Formula (side×side). The subtract the area of square from area of rectangle.

✎ •°Given :-

Length of rectangle = 26 cm

Breadths of rectangle = 16 cm

Side of square = 9 cm

✎To Find :-

• The area of the shaded region

✎Solution :-

Area of the Rectangle ,

$➛ \sf \large \: area =( length \times breadth) \\ \\ ➛ \sf \large \: area = 26 \times 16 \\ \\ \sf \large➛area = 416cm$

Area of the Square ,

$\sf \large \: ➛area = (side \times side) \\ \\ \sf \large \: ➛area = (9 \times 9) \\ \\ \sf \large \: ➛area = 81cm {}^{2}$

The Area of The Shaded Region =

$➛ \sf \large \: 416 - 81 \\ \\ \sf \large \: ➛335cm$

Hence The area of the shaded region is 335 CM.

➲ More Formulaes of Area

To Know :-

➠Area of the Square = a²

➠Area of the rectangle = length × Breadth

➠Area of rhombus = 1/2 ×d¹×d²

➠Area of parallelogram = Breadth × height

➠Area of Trapezium = 1/2 × { Sum of the parallel side's )×(height)

➠Area of Circle = πr² (r=redius)

➠Area of semi Circle = 1/2 πr² (r=radius)