Question

In the adjoining figure,find the following ratios:
tanx ,cos (90-y) ,Siny ,cos (90-x),tan(90-x) and sinx

Answer 1

Tan x = bd/ad
Cos(90-y)=cd/ad
Sin y= ad/ac
Cos (90-x)=bd/ab
Tan (90-x)=ad/bd
Sin x = bd/ab
Hope it helps

Answer 2

tan x = BD / AD

cos (90 - y) = AD / AC

sin y = AD / AC

cos (90 - x) = BD / AB

tan (90-x) = AD / BD  

sin x = BD / AB

• sin θ = perpendicular / hypotenuse

• cos θ = base / hypotenuse

• tan θ = perpendicular / base

• cot θ = base / perpendicular

• cosec θ = hypotenuse / perpendicular

• sec θ = hypotenuse / base

• sin (90 - θ) = cos θ

• cos (90 - θ) = sin θ

• tan (90 - θ) = cot θ