Question

in the adjoining figure, find the measure of ∆abc and ∆acd.


solve this

answer is ∆abd = 130°
∆acd=130°​

Answer 1

In ΔABC;

∠A + ∠ABC + ∠ACB = 180°  ( ANGLE SUM PROPERTY OF A Δ )

55° + ∠ABC + ∠ABC = 180°  ( ∠ABC = ∠ACB as AB = AC )

2∠ABC = 180 - 55

∠ABC = 62.5° = ∠ACB

In ΔBCD;

∠CBD + ∠BCD + ∠D = 180°

2∠BCD = 180 - 45

∠BCD = 67.5 = ∠CBD

Hence, ∠B = ∠CBD + ∠ ABC

                   = 67.5 + 62.5

                   = 130°

And, ∠C = ∠ACB + ∠ BCD

              = 67.5 + 62.5

              = 130°

Answer 2

Answer:

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