Question

In the adjoining figure, find the sum of angle A + Angle B + Angle C + Angle D + Angle E.​

Answer 1

Answer:

E = 360°/2 = 180°

Therefore, angle A + angle B + angle C + angle D + angle E = 180°

Step-by-step explanation:

et us find the sum of the interior angles of a heptagon.

Heptagon is a polygon with 7 sides.

⇒n=7

Sum of interior angles of a heptagon =(2×7−4)×90°

⇒10×90⇒=900

⇒900 °

One angle of a heptagone= 7

900

=128.57∘

So one angle of a triangle=180−128.57=51.43∘

Another angle is 180−102.85=77.14∘

So the sum of m∠A+m∠B+m∠C+m∠D+m∠E+m∠F+m∠G=77.17×7=540

Answer 2

$\huge\fbox \pink {A}\fbox \blue {n} \fbox \purple {s} \fbox \green{w} \fbox \red {e} \fbox \orange {r}$

Answer:

E = 360°/2 = 180°

Therefore, angle A + angle B + angle C + angle D + angle E = 180°

Let us find the sum of the interior angles of a heptagon.

Heptagon is a polygon with 7 sides.

⇒n=7

Sum of interior angles of a heptagon =(2×7−4)×90°

⇒10×90⇒=900

⇒900 °

One angle of a heptagone= 7

900

=128.57∘

So one angle of a triangle=180−128.57=51.43∘

Another angle is 180−102.85=77.14∘

So the sum of m∠A+m∠B+m∠C+m∠D+m∠E+m∠F+m∠G=77.17×7=540