In the adjoining figure, find the value of Angle OBC if Angle AOC = 52°,
where O is the centre of the circle.
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Answer:
angle OBC = 26°
OB = OC (radii)
therefore, triangle OBC is isoceles
since exterior angle equals two opposite interior angels,
angle O = angle B + angle C
but angle B = angle C (since triangle OBC is isoceles as mentioned above)
angle O = angle B + angle B
52 = 2B
52/2 = B
B = 26°
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