In the adjoining figure, find the value of x.
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We know that ABD and ADC are both right angled triangles .
In ABD AB=13cm and BD=5cm
So AD^2=AB^2-BD^2
=13cm^2-5cm^2
=169cm^2-25cm^2
=144cm^2
thus AD=12cm.
Now in ADC, we know that AC^2=DC^2+AD^2
=>15cm^2=12cm^2+X^2
=>225cm^2=144cm^2+x^2
=>(225-144)cm^2=x^2
=>81cm^2=x^2
THEREFORE x= 9cm.
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