in the adjoining figure find the value of x and y
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x=45 as AB parallel to DE
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triangle ABC is similar to the triangle ADE
angle ACB=angle DVR
I think you know
BC=CD
AD//DE
so x=45
3y+1=180-(53+45)
=180-98
=82
3y+1=82
=3y=81
=y=27
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angle ACB=angle DVR
I think you know
BC=CD
AD//DE
so x=45
3y+1=180-(53+45)
=180-98
=82
3y+1=82
=3y=81
=y=27
please follow me and tag me as brainlist
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