In the adjoining figure find x+y .
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Answer:
In triangle ABP
As angle =90°
By Pythagoras property
AP² = AB² + BP²
15² = 9² + x²
225 - 81 = x²
144 = x²
x = 12
In triangle CDP
Angel D = 90°
By Pythagoras property
PC² = PD² + CD²
15² = y² + 12²
225 = y² + 144
y² = 225 - 144
y² = 81
y = 9
x + y
12 + 9 = 21 m.
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