in the adjoining figure find x+y+z+w
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Answered by
57
z+70=180
z=110
x+130=180
x=50
y+80=180
y=100
70+80+130+?=360
?=360_ 280
=80
z=110
x+130=180
x=50
y+80=180
y=100
70+80+130+?=360
?=360_ 280
=80
Answered by
40
sum of all angles of quadrilateral=360
so,let unknown no be 'a'
130+80+70+a=360
280+a=360
a=360-280
a=80
x=180-130
=50
y=180-80
=100
z=180-70
=110
w=180-a
=180-80
=100
now,
x + Y + Z + w = 50 + 100 + 110 + 100
=360
from this we can prove that the sum of exterior angle of quadrilateral is 360
so,let unknown no be 'a'
130+80+70+a=360
280+a=360
a=360-280
a=80
x=180-130
=50
y=180-80
=100
z=180-70
=110
w=180-a
=180-80
=100
now,
x + Y + Z + w = 50 + 100 + 110 + 100
=360
from this we can prove that the sum of exterior angle of quadrilateral is 360
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