In the adjoining figure find z and y if PQ II BC
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Angle A + Angle B + Angle C
Angle A + 60 deg + 50 deg = 180 deg. ( Angle sum property of a triangle )
Angle A + 110 deg = 180 deg
Angle A = 180 - 110
Angle A = 70 deg
Now,
Angle A + Angle Y + Angle Z = 180 deg. ( Linear Pair )
70 deg + Angle Y + Angle Z = 180 deg
Angle Y + Angle Z = 180 - 70
Angle Y + Angle Z = 110 deg
Angle Y + Angle Z = 110/2
Angle Y = 55 deg
Angle Z = 55 deg
Hope this helps, Pls mark me as brainliest
Angle A + Angle B + Angle C
Angle A + 60 deg + 50 deg = 180 deg. ( Angle sum property of a triangle )
Angle A + 110 deg = 180 deg
Angle A = 180 - 110
Angle A = 70 deg
Now,
Angle A + Angle Y + Angle Z = 180 deg. ( Linear Pair )
70 deg + Angle Y + Angle Z = 180 deg
Angle Y + Angle Z = 180 - 70
Angle Y + Angle Z = 110 deg
Angle Y + Angle Z = 110/2
Angle Y = 55 deg
Angle Z = 55 deg
Hope this helps, Pls mark me as brainliest
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Answer:
Step-by-step explanation:
This is very simple!
See, In this figure if PQ║BC then AB is a transversal.
∴ ∠Y = 60° ( alternate interior angles)
Thus the same applies for line segment AC.
As AC is another transversal for PQ and BC.
∴ ∠Z = 50° (Alternate interior angles).
Now, finding the measure of the missing angle in the triangle.
Let the missing angle be x.
∴ ∠x = 180° - 110° ( Angle sum property of a triangle)
∴∠x = 70°
Now measure of ∠A would be 180° (straight angle).
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