in the adjoining figure fint the area of the shaded area
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WHAT IS THE SHADED PART??????
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54 cm2. EASY. Share. Study later. Answer. Diameter of the larger semi-circle, 2R=28 cm. ∴ Its radius R=14 cm. Diameter of smaller semi-circle, 2r=14 cm. Area of the shaded portion = (Area of large semi-circle) - 2 (Area of smaller semi-circle) = 21πR2−2(21πr2)=21π(R2−2r2)
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