Question

in the adjoining figure for the right angle triangle ABC and BCD AB/BC=1/2 FIND A(ABC)\A(BCD)

Answer 1

friend ,the answer will be 1 as because something is not mentioned here.............the triangles might be similar or it may be a pararrellogram.

Answer 2

Answer:

Step-by-step explanation:in triangle ABC and BDC :

∠abc = ∠bcd, ( each equal to 90)

bc = bc (common)

ab = cd (both are perpendicular)

therefore both triangles are congruent by RHS congruence criterion

area of triangle ABC/ area of triangle BDC = ab²/bc²                  (since : ratio of area of similar triangle is equal o the ratio of its corresponding sides)

⇒ ar(ΔABC)/ar(ΔBDC) = (1)²/(2)²

⇒ar(ΔABC)/ar(ΔBDC) = 1/4

i hope you will get your answer....