In the adjoining figure, if AB || DE, ∠ABC = 1100 and ∠CDE = 1100, find ∠BCD. (attachment — 3rd question)
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Lines and Angles
Transversals to Parallel Lines
In figure, AB∥ DE∥ PQ and ...
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Asked on December 26, 2019 by
Balwant Mech
In figure, AB∥DE∥PQ and ∠ABC=130
o
,∠CDE=110
o
. Find ∠BCD.
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∵PQ∥DE
∴∠CDE+∠DCQ=180
o
(co-interior angles are supplementary)
110
o
+∠DCQ=180
o
(∠CDE=110
o
)
∠DCQ=70
o
Similarly, AB∥PQ
∴∠ABC+∠PCB=180
o
(co-interior angles are supplementary)
130
o
+∠PCB=180
o
(∠ABC=130
o
)
∠PCB=50
o
∠PCB+∠BCD+∠DCQ=180
o
(Angle on same side of straight line)
50
o
+∠BCD+70
p
=180
o
∠BCD=180
o
−50
o
−70
o
=60
o
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