in the adjoining figure, if ABCD is an isosceles trapezium, its perimeter units using √2=1.41) 1 }is 17.64 units 15.64 units 452 (b) 18.64 units (d) 16.64 units
Attachments:
Answers
Answered by
2
Given : ABCD is an isosceles trapezium
√2 = 1.41
To Find : Perimeter of Trapezium
Solution:
Tan ∠D = AE/DE
=> tan 45° = 2/DE
=> 1 = 2/DE
=> DE = 2 unit
Sin 45° = AE/AD
=> 1/√2 = 2/AD
=> AD = 2√2 unit
Similarly CF = 2 units
BC = 2√2 units
EF = AB = 3 units
Perimeter of trapezium ABCD
AB + BC + CD + DA
AB + BC + (CF + EF + DE) + DA
= 3 + 2√2 + 2 + 3 + 2 + 2√2
= 10 + 4√2
= 10 + 4(1.41)
= 10 + 5.64
= 15.64
Perimeter of trapezium ABCD is 15.64 units
Correct option is C) 15.64 units
Learn More:
AB parallel CD in trapezium ABCD if angle A = Y + 60° and Angle B ...
brainly.in/question/8847570
trapezium ABCD in which ab is parallel to CD are 2 X + 50 and 2x ...
brainly.in/question/11100485
Similar questions