Math, asked by priyanshu394996, 9 hours ago

in the adjoining figure, if ABCD is an isosceles trapezium, its perimeter units using √2=1.41) 1 }is 17.64 units 15.64 units 452 (b) 18.64 units (d) 16.64 units​

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Answered by amitnrw
2

Given :  ABCD is an isosceles trapezium

√2 = 1.41

To Find : Perimeter of Trapezium

Solution:

Tan ∠D = AE/DE

=> tan 45° = 2/DE

=> 1 = 2/DE

=> DE = 2  unit

Sin 45° = AE/AD

=> 1/√2  = 2/AD

=> AD = 2√2 unit

Similarly CF = 2 units

BC = 2√2  units

EF = AB = 3 units

Perimeter of trapezium ABCD

AB + BC + CD + DA

AB + BC + (CF + EF + DE)  + DA

= 3 + 2√2 + 2 + 3 + 2 + 2√2

= 10 + 4√2

= 10 + 4(1.41)

= 10 + 5.64

= 15.64

Perimeter of trapezium ABCD is 15.64 units

Correct option is C) 15.64 units

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