Question

In the adjoining figure if ABCD is parallelogram state the test by which DBC and ABD are congruent?​

Answer 1

Answer:

angle ADB=angle DBC(alternate interior angle)

DB=DB(common)

angle A=angle C(opposite side of a parallelogram)

DBC congruent to ABD(by ASAcongruency)

Answer 2

Given : ABCD is parallelogram

To Find :   state the test by which DBC and ABD are congruent

Solution:

ABCD is a parallelogram

opposite sides of parallelogram are equal and parallel

hence  

            AD  = BC

           ∠BDA=∠DBC   ( alternate angle )

 and   Bd  = BD  coomon

    ΔBDA  ≅    ΔDBC   ( SAS)

( SAS)   test by which ΔDBC and     ΔBDA are congruent

but here in the question its given

DBC and ABD are congruent

which is not correct

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