Math, asked by Dhruv2019, 10 months ago

In the adjoining figure, if AD, AE and BC are tangents to the circle at D, E and F respectively, then
(1) AD = AB + BC + CA
(2) 2AD = AB + BC + CA
(3) 3AD = AB + BC + CA
(4) 4AD = AB + BC + CA

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Answered by Amanray18

0

Answer:

The right answer is (2) 2AD=AB+ BC + CA

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