Question

In the adjoining figure, if AD, AE and BC are tangents to the circle at D, E and F respectively, then
(1) AD = AB + BC + CA
(2) 2AD = AB + BC + CA
(3) 3AD = AB + BC + CA
(4) 4AD = AB + BC + CA​

Answer 1

Answer:

The right answer is (2) 2AD=AB+ BC + CA