. In the adjoining figure, if I || m, AF || BE, FC I m and
EDIm, then the correct statement is
(a) ar (II ABEF) = ar (rect. CDEF)
(b) ar (IIABEF) = ar(quad. CBEF)
(c) ar (II ABEF) = 2 ar(AACF)
(d) ar (IIABEF) = 2 ar (AEBD)
CB
Answers
Answered by
0
Answer:
may be b)
Step-by-step explanation:
I hope answers is correct
Similar questions