In the adjoining figure, if
Ki= 2K and K2=3K,
l1 =12=, A1 = A2 , find
the temperature of the interface o
in a steady state.
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Answer:
I don't know sorry
Answered by
0
Answer:
1.2k is the answer dear!!
Explanation:
We know that for the given condition, equivalent thermal conductivity will be given as:
K=L1K2+L2K1K1K2(L1+L2)
So putting these value in above formula we find,
Keq=5KL6K2(L)=1.2K
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