Question

In the adjoining figure, if PQ is perpendicular to PS, PSIISR, SQR=28° and QRT=65°, than find the values of x and y.​

Answer 1

Answer:

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Solution-

It is given that PQ∥SR. Therefore, ∠QRT=∠PQR (Alternate Interior Angles)

⇒65°=x+28°

⇒x=65°−28°=37°

In ∆PQS, we have

x+y+∠SPQ=180° (Sum of three angles of a triangle =180°)

⇒37°+y+90°=180° ( It is given that ∠SPQ=90°)

⇒y=180°-37°−90°=53°

Therefore, x=37° and y=53°

I hope, this will help you.☺

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