Question

in the adjoining figure, if PQ RS. SHOW THAT PR QS

Answer 1

Given. PQ=RS
To prove. PR=QS
proof.
PQ=RS
Add QR in both side
PQ+QR=RS+QR
PR=QS
Hence proved

Answer 2

PR = QS

Step-by-step explanation:

The correct question: In the given figure, if PQ = RS then show that PR = QS.

Given data:

PQ = RS

Consider PQRS as a straight line, where P, Q, R and S are points on the straight line.

PQ = RS

Add QR on both sides by using addition postulate.

PQ + QR = QR + RS

By segment addition QR + RS = PR

PQ + QR = PR ------- (1)

Similarly,

QR + RS = QS (By segment addition) ------- (2)

From (1) and (2),

PQ + QR = QR + RS

PR = QS

Hence proved.

To learn more...

1. If PR = QS,then prove that PQ=RS on a line segment

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2. In the given figure PR=QS then show that PQ=RS name which Euclid's axiom or postulate is used for the same

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