In the adjoining figure , If Seg PR ≅ Seg PQ, Show that Seg PS > Seg PQ.
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In APRS, ZPRS is an obtuse angle.
Since, a traingle can have maximum one
obtuse angle.
Hence, ZPRS is the greatest angle.
Therefore, the side opposite to ZPRS i.e., PS is
the longest side.
Now, seg PS > seg PR > seg RS
.. seg PS > seg PQ .. [seg PR seg PQ]
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