Question

In the adjoining figure, if the area of the parallelogram ABCD is 150 sq.cm
the area of AADE is :
(a) 150 sq.cm.
(b) 75 sq.com
(c) sq.cm.
(d) 15 sq.cm.​

Answer 1

75 sq.cm is your answer

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Answer 2

Area of the Δ ADE =  75 $cm^{2}$

Thus Option B is correct.

Step-by-step explanation:

Given data

Area of the parallelogram ABCD = 150$cm^{2}$

⇒ AB × AD = 150$cm^{2}$ ------ (1)

From the figure Area of the triangle is given by A = 0.5 × AD × EF

Since EF = AB

⇒ Area of the triangle ADE = 0.5 × AD × AB

Put the values of AD & AB  From equation (1) in above equation we get

⇒ Area of the  Δ ADE  = 0.5 × 150

⇒ Area of the Δ ADE  = 75 $cm^{2}$

Therefore area of the Δ ADE is = 75 $cm^{2}$

Thus Option B is correct.