Math, asked by shushmamishra5002, 11 months ago

In the adjoining figure,
if triangleABN = triangleACM.
Show that triangleAMN similar to
traingleABC.

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Answers

Answered by TheOdd1sOut

0

Answer:

Step-by-step explanation:

Angle a is common.

And,

Am/BM=AN/CN (SIDES ARE PROPTIONAL)

HENCE BOTH THE TRIANGLES ARE SIMILAR THROUGH SAS

PLZ MRK AS BRAINLIEST.......

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