In the adjoining figure,
in A ABC, seg AD and seg BE are altitudes and
AE = BD. Prove that seg AD = seg BE.
B
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Answer:
Given:- AD and seg BE are altitudes and
AE = BD
To Proof That:- seg AD = seg BE
Proof:- In ∆ ABE and ∆ BAD
AE = BD (given)
angle EAB = angle DBA (opp. angle of
equal side)
ED = ED ( Common)
therefore ∆ ABE ≈ ∆ BAD (SAS test)
therefore, seg AD = seg BE. (C.P.C.T.)
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