Question

in the adjoining figure is equals to 80 degree ad and CD are bisector of B and angle C respectively then find angle bdc​

Answer 1

Answer:

In triangle ABC angle A + Angle B +angle C = 180 Deg

Angle B +angle C = 180 Deg- angle A

=180-80=100 deg

In triangle BDC angle DBC + angle DCB + BDC = 180 deg

angle DBC = 1/2 angle B ( angular bisectors)

angle DCB = 1/2 angle C

In triangle BDC 1/2 angle B +1/2 angle C + BDC = 180 deg

In triangle BDC 1/2 (angle B + angle C) + BDC = 180 deg

=1/2(100)+BDC= 180 deg

angle BDC = 180 -50

angle BDC= 130 deg

Answer 2

Answer:

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