in the adjoining figure is equals to 80 degree ad and CD are bisector of B and angle C respectively then find angle bdc
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In triangle ABC angle A + Angle B +angle C = 180 Deg
Angle B +angle C = 180 Deg- angle A
=180-80=100 deg
In triangle BDC angle DBC + angle DCB + BDC = 180 deg
angle DBC = 1/2 angle B ( angular bisectors)
angle DCB = 1/2 angle C
In triangle BDC 1/2 angle B +1/2 angle C + BDC = 180 deg
In triangle BDC 1/2 (angle B + angle C) + BDC = 180 deg
=1/2(100)+BDC= 180 deg
angle BDC = 180 -50
angle BDC= 130 deg
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hey this is from pk Garg na
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