Question

In the adjoining figure it is being given that AO is parallel to CD, OB parallel to CE and angle AOB =50 degree. Find the measure of angle ECD

Answer 1

Answer:

∠ECD = 130°

Explanation:Given that, AO ∥ CD, OB ∥ CE and

• ∠AOB = 50°
• ∠AOD = ∠CDB = 50° [∵ Corresponding angles are equal] Then,
• ∠ECD + ∠CDB = 180° … [∵ Consecutive interior angles are supplementary]
• ∠ECD + 50 = 180
• ∠ECD = 180 – 50
• ∠ECD = 130°

Answer 2

no digram, but I found the answer for you searching in ncert 7th grade

Given: AO∥ CD OB ∥CE ∠AOB = 50°∠AOD = ∠CDB = 50° (when AO∥ CD and OB is the transversal)∠ECD +∠CDB = 180° (consecutive interior angles are supplementary, DB ∥CE and CD is the transversal)∠ECD = 180°−50° = 130°