In the adjoining figure it is being given that AO is parallel to CD, OB parallel to CE and angle AOB =50 degree. Find the measure of angle ECD
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Answer:
∠ECD = 130°
Explanation:Given that, AO ∥ CD, OB ∥ CE and
- ∠AOB = 50°
- ∠AOD = ∠CDB = 50° [∵ Corresponding angles are equal] Then,
- ∠ECD + ∠CDB = 180° … [∵ Consecutive interior angles are supplementary]
- ∠ECD + 50 = 180
- ∠ECD = 180 – 50
- ∠ECD = 130°
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no digram, but I found the answer for you searching in ncert 7th grade
Given: AO∥ CD OB ∥CE ∠AOB = 50°∠AOD = ∠CDB = 50° (when AO∥ CD and OB is the transversal)∠ECD +∠CDB = 180° (consecutive interior angles are supplementary, DB ∥CE and CD is the transversal)∠ECD = 180°−50° = 130°
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