Question

In the adjoining figure, it is given that CE || BA, ZBAC = 80°
and ZECD = 35°
Find (i) ZACE, (ii) ZACB, (iii) ZABC.​

Answer 1

(i) ∠BAC

=∠ACE=80⁰   ....[∴ Alternate angles]

(ii) ∠ACB

=∠ACB+∠ACD=180o     ....[∴ Linear pair]

=∠ACB+∠ACE+∠ECD=180o

=∠ACB+80+35=180

=∠ACB+125=180

=∠ACB=180−115

=∠ACB=65o

(iii) ∠ABC

Let us consider △ABC,

 ∠ABC+∠ACB+∠BAC=180⁰

=∠ABC+65+80=180⁰

=∠ABC+145=180

=∠ABC=180−145

=∠ABC=35⁰

Answer 2

Answer:

Aapka 2nd vaala sahi to hai but uska easy tarika hai ki vo thirty five ke vertically opposite angle hai