In the adjoining figure, it is given that LA = 60°.CE | BA and
ECD=65. Ford ZACB.
CEBA and AC is a transversal
ZACE = _BAC =60 (alternate angles)
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Step-by-step explanation:
A/ Image.
<A = 60°
CE II AB <ECD = 65°
(Interior Alternate Angle)
<BAC = <ACE
<ACE = 60°
<BCD = 180° (linear Angle) or (linear
Point)
<ACB +< LCE + <ECD = 180°
<ACH = 180° - (60 + 65)
= 180° - (125)
<ACB = 55°
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