In the adjoining figure l parallel m and P parallel q find the value of a, b, c and d
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∠b is transversal angle of 60°
So ∠b=60°
∠a+∠b=180°
∠a + 60° = 180°
∠a=120°
∠b and ∠c are vertically opposite.
So, ∠c=60°
∠c is complementary angle of ∠d.
So, ∠c+∠d=180°
∠d = 180-60 = 120°
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