Question

In the adjoining figure LB = 40 and AD Il EF, LFEB = 85. (2) Find: i) BCD ii) BAC of 9 cbse only thes sum on only​

Answer 1

As per the diagram, lines CD∣∣EF and CE is transveral.

We know that sum of interior angles is equal to 180

o

∠ECD+∠CEF=180

o

∠ECD+130

o

=180

o

∠ECD=180−130

o

∠ECD=50

o

As per the diagram, lines AB∣∣CD and CA is transveral.

We know that alternate angles are equal.

∠BAC=∠ACD

∠BAC=∠ACE+∠ECD

70

o

=∠ACE+50

o

20

o

=∠ACE

∴∠ACE=20

o

$As per the diagram, lines CD∣∣EF and CE is transveral.</p><p></p><p></p><p>We know that sum of interior angles is equal to 180o</p><p></p><p></p><p>∠ECD+∠CEF=180o</p><p></p><p></p><p>∠ECD+130o=180o</p><p></p><p></p><p>∠ECD=180−130o</p><p></p><p></p><p>∠ECD=50o</p><p></p><p></p><p>As per the diagram, lines AB∣∣CD and CA is transveral.</p><p></p><p></p><p>We know that alternate angles are equal.</p><p></p><p></p><p>∠BAC=∠ACD </p><p></p><p></p><p>∠BAC=∠ACE+∠ECD</p><p></p><p></p><p>70o=∠ACE+50o</p><p></p><p></p><p>20o=∠ACE</p><p></p><p></p><p>∴∠ACE=20o</p><p></p><p></p><p>$

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