Question

in the adjoining figure line BD and AC intersect each other at point P. m∆ APB-=34° then find m∆APD And m∆BPC​

Answer 1

Step-by-step explanation:

∠APD and ∠APB are angles in a linear pair. ∴m∠APD + m∠APB = 180° ∴47 + m∠APB = 180 ∴47 + m∠APB – 47 = 180 – 47 …. (Subtracting 47 from both sides) ∴m∠APB = 133° m∠CPD = m∠APB = 133° … .(Vertically opposite angles) m∠BPC = m∠APD = 47° … .(Vertically opposite angles) ∴The measures of ∠APB, ∠BPC and ∠CPD are 133° , 47° and 133° respectively