Math, asked by nandananda02549, 8 months ago

In the adjoining figure line m parellel line n line pand line q are transvers
al find measure of angle x and angle y ​

Answers

Answered by Anonymous
5

Step-by-step explanation:

40° +u=180∘

⇒u=140∘

ω+u=180∘

⇒ω=180°−u

=40°

∠z=70°(vertically opposite angles)

∠y+∠z=180°

⇒∠y=180°−∠z

180°−70°

=110°

⇒ω+x=180∘

∴x=140∘

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Answered by Nitindkkw
3

Question ★In the adjoining figure line m parellel line n line pand line q are transvers

al find measure of angle x and angle y

ANSWER

40

40 ∘

40 ∘ +u=180

40 ∘ +u=180 ∘

40 ∘ +u=180 ∘

40 ∘ +u=180 ∘ ⇒u=140

40 ∘ +u=180 ∘ ⇒u=140 ∘

40 ∘ +u=180 ∘ ⇒u=140 ∘

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘ ∴x=140

40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘ ∴x=140 ∘

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