In the adjoining figure line m parellel line n line pand line q are transvers
al find measure of angle x and angle y
Answers
Step-by-step explanation:
40° +u=180∘
⇒u=140∘
ω+u=180∘
⇒ω=180°−u
=40°
∠z=70°(vertically opposite angles)
∠y+∠z=180°
⇒∠y=180°−∠z
180°−70°
=110°
⇒ω+x=180∘
∴x=140∘
please mark as brainlist answer and follow me please thank answer
Question ★In the adjoining figure line m parellel line n line pand line q are transvers
al find measure of angle x and angle y
ANSWER ❒
40
40 ∘
40 ∘ +u=180
40 ∘ +u=180 ∘
40 ∘ +u=180 ∘
40 ∘ +u=180 ∘ ⇒u=140
40 ∘ +u=180 ∘ ⇒u=140 ∘
40 ∘ +u=180 ∘ ⇒u=140 ∘
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘ ∴x=140
40 ∘ +u=180 ∘ ⇒u=140 ∘ ω+u=180 ∘ ⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180 ∘ ∴x=140 ∘
100percent verified solution
Step-by-step explanation: