Question

in the adjoining figure, line pa and rs intersect each other at o. of pqr:pqs=5:7. find all the angles

pls help re anyone...
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Answer 1

Answer:

∠POR+∠ROQ=180

o

(Linear pair of angles)

But ∠POR:∠ROQ=5:7 (Given)

Therefore, ∠POR=

12

5

×180=75

o

Similarly, ∠ROQ=

12

7

×180=105

o

Now, ∠POS=∠ROQ=105

o

(Vertically opposite angles)

and ∠SOQ=∠POR=75

o

(Vertically opposite angles)

Answer 2

Answer:

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