Question

In the adjoining figure , lines AB and CD intersect at F. If angle EFC =angle AFC and angle angle CBF =50° , find angle EFC . ​

Answer 1

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Answer 2

$\huge\rm\underline\red{Question:-}$

In the adjoining figure , lines AB and CD intersect at F. If angle EFC =angle AFC and angle angle CBF =50° , find angle EFC .

$\huge\underline\frak{\fbox\green{Given:-️}}$

lines AB and CD intersect at F. If angle EFC =angle AFC and angle angle CBF =50°.

$\bf \huge \fbox \blue{ \: \: \: Solutions:-\: \: \: \: }$

In the figure,

angle EFC =angle AFC

Let angle EFC and angle AFC be x.

we know that ,

sum of measure of all angles = 180

of triangle

:. x +x+50 = 180

:. 2x = 180 - 50

➡️ 2x = 130

➡️

$x = \frac{130}{2}$

therefore,

x = 65°

angle EFC = x = 65°

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Ans:- Angle EFC is 65°

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