in the adjoining figure lines AB and CD intersect at F. if ZEFA=ZAFD and ZCFB=50°,find ZEFC
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answer to the above question is given in the attachment
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Answer:
<EFC = 80 Degree.
Step-by-step explanation:
<CFB = 50 degree
<CFB = <AFD [Vertically Opposite angles]
<AFD = 50 degree
<EFA = <AFD [Given]
<EFD = 50 degree
We know that,
<EFA + <EFC + <CFB = 180 degree [ Straight Angle]
50 + <EFC + 50 = 180 degree
100 + <EFC = 180 degree
<EFC = 180 - 100
<EFC = 80 Degree.
There you go!
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