in the adjoining figure lines ab and CD intersect at f.<EFA=<AFD and<CFB =50 degree find <EFC
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Step-by-step explanation:
Angle efa+angle afd+angle efc=180 degrees (linear pair)
Afd=50 degree (vertically opposite)
50+50+efc=180 degree
Hence efc=80 degree
Hope it helps you
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