Question

In the adjoining figure LM║AB. If AL=x-3, AC=2x,BM=x-2 and BC=2x+3. Find x.

Answer 1

SOLUTION

Let ABC be a ∆ such that LM||AB.

Then by thales theorem

=) AL/LC= BM/MC

=) AL/AC-AL = BM/BC-BM

=) x-3/2x-(x-3) = x-2/(2x+3)-(x-2)

=) A/Q

=) x-3/2x-x+3 = x-2/2x+3-x+2

=) x-3/x+3= x-2/x+5

=)(x-3)(x+5)= (x+3)(x-2)

=) x^2 +5x-3x-15= x^2-2x+3x-6

=) 2x-15= x-6

=) 2x-x= -6+15

=) x= 9

hope it helps ☺️

Answer 2

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Answer:

$x = 9$

Step-by-step explanation:

Pls Follow the attachment Frnd.

Hope this helps.✌️

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