In the adjoining figure not drawn to scale AB is a tower and two objects C &D are located on the ground on the same side of AB. when observed from top A of tower their angles of depression are 45° & 60°. Find distance between two objects if height of tower is 300m. Give answer to the nearest metre.
Answers
Given : AB is a tower and two objects C &D are located on the ground on the same side of AB. when observed from top A of tower their angles of depression are 45° & 60° . height of tower = 300 m
To find : distance between two objects
Solution:
angles of depression = Angle of elevation
Tan 45° = AB/BC
=> 1 = 300/BC
=> AC = 300 m
Tan 60° = AB/BD
=> √3= 300/BD
=> AD = 100√3 m
distance between two objects = CD = BC - BD
= 300 - 100√3 m
= 100 ( 3 - √3 ) m
= 126.8 m
= 127 m ( nearest meter )
127 m is the distance between two objects
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Step-by-step explanation:
AC =300 m is wrong there should be BC=300m