In the adjoining figure NQ bisects ZMNP, MN = 25, NP = 40, MQ = 14 find QP.
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In ∆MNP, seg NQ bisects ∠N. [Given]
∴ PN/MN = QP/MQ [Property of angle bisector of a triangle]
∴ 40/25 = QP/14
∴ QP = (40 x 14)/25
∴ QP = 22.4 units
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Answer:
- 40/25=QP/14
- QP=(40>< 14)/25
- QP=22.4 units
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