Question

In the adjoining figure O is center of the circle, OA=10cm and OC=6cm find the length of AB​

Answer 1

Step-by-step explanation:

Given OA=10cm

OC=6cm

∠OCA= 90

∘

By Pythagoras theorem,

AC

2

=OA

2

−OC

2

=10

2

−6

2

AC=8cm

We know that perpendicular from centre of circle bisects the chord

Therefore AB=2AC

• AB=16cm