In the adjoining figure O is the centre of circle and diameter AC = 26 cm. If chord AB = 10 cm, then the distance between chord AB and centre O of the circle is :
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12CM
STEP OF EXPLANATION;
AC=26cm
OA=13cm
AB=10cm
AM=5cm
IN TRIANGLE AMO;
OM²+AM²=OA²
OM²+5²=13²
OM²=169-25
OM²=144
OM=√144
OM=12cm
so,the distance between chord AB and centre O of the circle is : 12cm
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