Question

in the adjoining figure o is the centre of the circle find the value of angle ABP if angle POB = 90 degree​

Answer 1

Answer:

angle AOB=100

angle ACB=50 (angle made at centre is double the angle made at any other point)

now,ACBD is a cyclic quadrilateral , so angle ADB + angle ACB=180 ( sum of opposite angles of a cyclic quad. is 180)

therefore,angle ADB=180-50=130

ANSWER IS 130°

hope it helped.

Answer 2

Answer:                                  

GIVEN BELOW

Explanation:angle AOB=100

angle ACB=50 (angle made at centre is double the angle made at any other point)

now,ACBD is a cyclic quadrilateral , so angle ADB + angle ACB=180 ( sum of opposite angles of a cyclic quad. is 180)

therefore,angle ADB=180-50=130

ANSWER IS 130°