In the adjoining figure, O is the centre of the circle, find the measure of angle X
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40 degrees
BOD is a diameter
Angle BAD is 90 degrees(angle in a semicircle is 90 degress)
so angle ABD is 40 degrees
angle ABD is equal to angle ACD(angle in the same segment)
x=40 degrees
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<CDO = X , as triangle cod is isoceles triangle
<ADC =90⁰ , as angle subtended by diameter in circle
50+x =90
x = 40
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