Question

In
the
adjoining
figure
,
O
is
the
centre
of
the
circle
.
IF
AOB
=
110
°
,
then
BCD​

Answer 1

Step-by-step explanation:

let the BCD is X

A.T.Q

If AOB= 110°

A angel is of 180°

AOB+X°=180°

110°+X=180°

X= 180°-- 110°

X=70°

BCD = 70°

Therefore the answer is 70°