Question

In the adjoining figure O is the centre of the circle. With reference to the dollowinf fill in the blanks

•Seg OD is _________of the circle.
•Seg AB is _________of the circle.
•Seg PQ is _________of the circle.
•__________ is the central angle.
• Minor arc: arc AXD, arc BD, ____,____,____.
• Major arc: arc PAB, arc PDQ,______
•Semicircular arc: arc ADB,________
•m (arc DB) = m angle______
•m (arc DAB)= 360°- m angle____​

Answer 1

•$Seg\: OD\: is\: \underline { \pink { radius }}\:of \: the \: circle.$

•$Seg\: AB\: is\: \underline { \pink { diameter}} of\: the\: circle.$

•$Seg\: PQ\: is\: \underline { \pink { chord}}\:of \:the\: circle.$

•$\underline { \pink { \angle {AOB }}}\:is\: the\: central\: angle.$

• $Minor\: arc: \:arc \:AXD, \:arc \:BD,\: \underline { \pink { arc\: BQ, \:arc\: PQ, \: arc\: PA }}$

• $Major \:arc:\: arc\: PAB, \:arc \: PDQ,\: \underline { \pink { arc\: AXQ ,\:arc\: DQA}}$

•$Semicircular\: arc:\: arc\: ADB\: \underline { \pink {arc \: AOB }}.$

•$m (arc \:DB) = m\: angle\: \underline {\pink {360\degree - m( arc\:DOB)}}$

•$m (arc \:DAB) = 360\degree - m \underline {\pink { \angle {DOB}}}$

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Answer 2

Step-by-step explanation:

•Seg\: OD\: is\: \underline { \pink { radius }}\:of \: the \: circle.SegODis

radius

ofthecircle.

•Seg\: AB\: is\: \underline { \pink { diameter}} of\: the\: circle.SegABis

diameter

ofthecircle.

•Seg\: PQ\: is\: \underline { \pink { chord}}\:of \:the\: circle.SegPQis

chord

ofthecircle.

•\underline { \pink { \angle {AOB }}}\:is\: the\: central\: angle.

∠AOB

isthecentralangle.

• Minor\: arc: \:arc \:AXD, \:arc \:BD,\: \underline { \pink { arc\: BQ, \:arc\: PQ, \: arc\: PA }}Minorarc:arcAXD,arcBD,

arcBQ,arcPQ,arcPA

• Major \:arc:\: arc\: PAB, \:arc \: PDQ,\: \underline { \pink { arc\: AXQ ,\:arc\: DQA}}Majorarc:arcPAB,arcPDQ,

arcAXQ,arcDQA

•Semicircular\: arc:\: arc\: ADB\: \underline { \pink {arc \: AOB }}.Semicirculararc:arcADB

arcAOB

.

•m (arc \:DB) = m\: angle\: \underline {\pink {360\degree - m( arc\:DOB)}}m(arcDB)=mangle

360°−m(arcDOB)

•m (arc \:DAB) = 360\degree - m \underline {\pink { \angle {DOB}}}m(arcDAB)=360°−m

∠DOB

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