In the adjoining figure O is the centre of the circle with radius or A B C D E and F are the diameters of the circle is equal to 4 c b equal to 60 degree what is the area of the shaded region
Answers
Answer:
Let the center of circle be at O. AC is diagonal of square ABCD
AC=4
2
cm
we have AE=CF=1cm each
EF=AC−AE−CF
EF=4
2
−2
radius of circle =
2
1
EF=2
2
−1
Area of shaded region = area (ABCD) − area of circel − 4\times area of each quadrant
=4×4−π×(2
2
−1)
2
−4×
4
1
π(1)
2
=16−π{(2
2
−1)
2
+1}
=16−π{8+1−4
2
+1}
=16−(10−4
2
)π
=16−13.64439
Area =2.36cm
2
Answer:
In the adjoining figure O is the centre of the circle with radius or A B C D E and F are the diameters of the circle is equal to 4 c b equal to 60 degree what is the area of the shaded region
Step-by-step explanation:
In the adjoining figure O is the centre of the circle with radius or A B C D E and F are the diameters of the circle is equal to 4 c b equal to 60 degree what is the area of the shaded regionfind the sum of order and degree of the differential equation: (dy/dx)^5+3xy(d^3 y/dx^3)^2+y^2(d^2 y/dx^2)^3=0.. Please solve this question as soon as possible..the below figure, the value of ZADC is:
a 60°
b. 30
0, 45°
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The
area
of
a
square
and
rectange
are
equal
.
If
the
side
of
the
square
is
100
m
and
the
length
of
the
rectangle
is
125
m
.
find
the
breadth
of
the
rectangle. Also find the perimeter of a square and a rectangle