Question

in the adjoining figure,O is the mid point of AD and BC.show that ∆AOB cong ∆DOC.pleasesolve it​

Answer 1

Answer:

In ∆ AOB And∆ DOC

AO = OD

CO = OB

Angel Aob = angle cod Vertically opposite angel

∆AOB =~ COD ( SAS)

Answer 2

Step-by-step explanation:

AO=OD

BO= OC

angle O= angle O

by the criteria of SAS. ....we say that these both

triangles were congruent.