Question

In the adjoining figure, OD 1 OC. Find
angleAOD + angleCOB.​

Answer 1

AOD=30°

AOD=30°COD=90°

AOD=30°COD=90°COB=X°

AOD=30°COD=90°COB=X°A.T.P.,

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°120° + X° = 180°

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°120° + X° = 180°X° = 180° - 120°

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°120° + X° = 180°X° = 180° - 120°X° = 60°