Math, asked by princie25, 10 months ago

In the adjoining figure, OD 1 OC. Find
angleAOD + angleCOB.​

Answers

Answered by dewangbata1212
1

AOD=30°

AOD=30°COD=90°

AOD=30°COD=90°COB=X°

AOD=30°COD=90°COB=X°A.T.P.,

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°120° + X° = 180°

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°120° + X° = 180°X° = 180° - 120°

AOD=30°COD=90°COB=X°A.T.P.,AOD+COD+COB=180°. (ANGLE SUM PROPERTY OF TRIANGLE)30° + 90° + X° = 180°120° + X° = 180°X° = 180° - 120°X° = 60°

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