in the adjoining figure of trapezium ABCD, AB = 24 cm,
DC = 15 cm, BD = 26 cm, DA I AB. Find the area of
trapezium.
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Answer:
195 cm ^2
Step-by-step explanation:
Area of trapezium
BD^2=AD^2 -AB^2
20^2=AD 12-24^2
26^2+ 24^2=AD^2
50 =AD^2
2√5=AD
area of ABCD
1/2 x (15+24)+2√5
39x5=195 cm^2
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