Question

In the adjoining figure, OPQRS is a trapezium. SR || PO. ZS 45°, ZR 30°,
PQ=4, QR = 12 then find the length of SR. plzz answer me fast..​

Answer 1

Step-by-step explanation:

PQ will be equal to AB .

PQ=AB=4

NOW IN TRAINGLE BQR angle q will be 60.

BR= 12cos(30).

QB=12sin(30)

and

QB=PA

THEREFORE PA=12sin(30)

In traingle PAS

angle p will also be 45.

son trangle PAS will isosceles

SA=PA

we know PA=12sin(30)

therefore SA=12sin(30)

so finally.

SR= SA+AB+BR

SR=12sin(30)+4+12cos(30)

SR=6+4+6root(3)

SR=10+root(3)

Answer 2

Given :   PQRS is a trapezium. SR ||PQ. ∠S=45°, ∠R=30°

PQ = 4

QR = 12

To Find : Length of SR

Solution:

Sin 30°  = BQ/ RQ

=> 1/2 = BQ/12

=> BQ = 6

PQ = BQ = 6

Cos 30° = BR/ RQ

=> √3/2  = BR/12

=> BR  = 6√3

AB = PQ = 4

Tan 45° = PA/AS

=> 1  =  6 / AS

=> AS = 6

SR = AS + AB  + BR

= 6 + 4  + 6√3

= 10  + 6√3

= 20.39

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